If ax+by+c=0, bx+cy+a=0 & cx+ay+b=0 are concurrent if a³+b³+c³ = 3abc @EAG

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If a+b+c=0,show that a³+b³+c³=3abc?#expansion#class9#selinasolutions#maths If a+b+c=0,show that a³+b³+c³=3abc?#expansion#class9#selinasolutions#maths
a3 + b3 + c3 - 3abc = ? (A Cube+ B Cube + C Cube- 3abc ) Formula of a cube plus b cube plus c cube a3 + b3 + c3 - 3abc = ? (A Cube+ B Cube + C Cube- 3abc ) Formula of a cube plus b cube plus c cube
If a+b+c=0 Then prove that a³+b³+c³=3abc. Easy Step-by-Step Explanation! If a+b+c=0 Then prove that a³+b³+c³=3abc. Easy Step-by-Step Explanation!
√(𝑎+𝑏𝑥)+√(𝑏+𝑐𝑥)+√(𝑐+𝑎𝑥)=√(𝑏−𝑎𝑥)+√(𝑐−𝑏𝑥)+√(𝑎−𝑐𝑥) √(𝑎+𝑏𝑥)+√(𝑏+𝑐𝑥)+√(𝑐+𝑎𝑥)=√(𝑏−𝑎𝑥)+√(𝑐−𝑏𝑥)+√(𝑎−𝑐𝑥)
a³ + b³ + c³ — 3abc = a³ + b³ + c³ — 3abc =
Solving Ax=0 Solving Ax=0
if a+b+c=0 then a^3+b^3+c^3=3abc #maths if a+b+c=0 then a^3+b^3+c^3=3abc #maths
04 vector calculus | the value of vectors a x (b+c)+ b x (a+c)+ c x (a+b) is 04 vector calculus | the value of vectors a x (b+c)+ b x (a+c)+ c x (a+b) is