lim_(x→π/4) (8√2-(cos⁡x+sin⁡x)^7)/(√2-√2 sin⁡2x) is equal to I Limits JEE PYQs Ashish Sir

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JEE Main 2022: lim(x→π/4) 8√2 - (cos x + sin x)⁷/√2-√2 sin2x is equal to JEE Main 2022: lim(x→π/4) 8√2 - (cos x + sin x)⁷/√2-√2 sin2x is equal to
lim┬(x→π/4)⁡〖(8√2-(cos⁡〖x+sin⁡x 〗 )^7)/(√2-√2 sin⁡2x )〗 is equal to lim┬(x→π/4)⁡〖(8√2-(cos⁡〖x+sin⁡x 〗 )^7)/(√2-√2 sin⁡2x )〗 is equal to
Value of the Limit of 8√2-(cos x+sin x)^7 /√2-√2sin 2x for x tends to π/4 is equal to:| IITJEE Maths Value of the Limit of 8√2-(cos x+sin x)^7 /√2-√2sin 2x for x tends to π/4 is equal to:| IITJEE Maths
lim┬(x→0)⁡〖(sin⁡(π〖cos〗^2 x))/x^2 〗 is equal to_____ lim┬(x→0)⁡〖(sin⁡(π〖cos〗^2 x))/x^2 〗 is equal to_____
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Q) The number of solutions of |cos𝑥|=sin𝑥, such that −4𝜋≤𝑥≤4𝜋 #jee #maths #jee2026 #jee2025 #ma Q) The number of solutions of |cos𝑥|=sin𝑥, such that −4𝜋≤𝑥≤4𝜋 #jee #maths #jee2026 #jee2025 #ma
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Functions IIT Questions NO 11 ( X Class) Functions IIT Questions NO 11 ( X Class)