Prove that area of triangle inscribed in the parabola y2 = 4ax is 1/8a(y1 - y2)(y2 - y3)(y3 - y1)

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Show that the area of the triangle inscribed in the parabola y^2=4 a x is : 1/8 a|(y_1-y_2)(y_2-y... Show that the area of the triangle inscribed in the parabola y^2=4 a x is : 1/8 a|(y_1-y_2)(y_2-y...
Area of the triangle inscribed in a Parabola is 1/8a |(y1 - y2)(y2 - y3)(y3 - y1)| Sq.units @EAG Area of the triangle inscribed in a Parabola is 1/8a |(y1 - y2)(y2 - y3)(y3 - y1)| Sq.units @EAG
#toon aan dat de oppervlakte van de driehoek ingeschreven in de parabool y²=4ax gelijk is aan 1/8... #toon aan dat de oppervlakte van de driehoek ingeschreven in de parabool y²=4ax gelijk is aan 1/8...
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