n-1Cr=(k^2-8)nCr+1, if and only if #iitjee2024

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n-1Cr= (k2-8)nCr+1 if and only if... n-1Cr= (k2-8)nCr+1 if and only if...
Condition involving n-1Cr = (k2-8)nCr+1 if and only if Condition involving n-1Cr = (k2-8)nCr+1 if and only if
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(n-1)Cr =(k^2-8).nCr+1, then set of the value of k (n-1)Cr =(k^2-8).nCr+1, then set of the value of k