Integrate 0 to pi/2 (2log sin x-log sin2x) II Integral of 2log sin x-log sin2x from 0 to pi/2 II

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integrate 0 to pi/2 integrate 0 to pi/2 '2log(sinx)-log(sin(2x))' dx || `int_(0)^((pi)/(2))(2log sin x- log sin 2x)dx`
Integration(2log sin x–log sin2x) dx from 0 to pi/2 Integration(2log sin x–log sin2x) dx from 0 to pi/2
Q10 | Integration of 2 log sin x minus log sin 2x | Integrate 0 to π/2 of 2log(sinx)-log(sin2x) Q10 | Integration of 2 log sin x minus log sin 2x | Integrate 0 to π/2 of 2log(sinx)-log(sin2x)
`int_(0)^((pi)/(2))(2log sin x- log sin 2x)dx` `int_(0)^((pi)/(2))(2log sin x- log sin 2x)dx`
The value of `int_(0)^(pi//2) (2log sin x-log sin 2x)dx`, is The value of `int_(0)^(pi//2) (2log sin x-log sin 2x)dx`, is
int_(0)^(pi//2) [2log sin x-log sin 2x] dx= | CLASS 12 | DEFINITE INTEGRAL | MATHS | Doubtnut int_(0)^(pi//2) [2log sin x-log sin 2x] dx= | CLASS 12 | DEFINITE INTEGRAL | MATHS | Doubtnut
Q45 | Integral 0 to pi/2 2 log sin x - log sin 2x dx | Integrate 2 log sin x - log sin 2x dx from 0 Q45 | Integral 0 to pi/2 2 log sin x - log sin 2x dx | Integrate 2 log sin x - log sin 2x dx from 0
Evaluate integrate 0 to pi /2 [log(sin x) - log(2cos x)] dx from 0 to pi/2 | ∫ log(sinx) -log(2cosx) Evaluate integrate 0 to pi /2 [log(sin x) - log(2cos x)] dx from 0 to pi/2 | ∫ log(sinx) -log(2cosx)