Let f(-1, 1 ) →R be continuous function , then the integral ∫_0^π▒〖f (sinx)dx 〗 is equvalent to

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If f:[0,1]→R is a continuous function, then ⁡∫(nf(x))/(1+n^2 x^2 )dx→π/2 f(0) as n→∞. If f:[0,1]→R is a continuous function, then ⁡∫(nf(x))/(1+n^2 x^2 )dx→π/2 f(0) as n→∞.