#How to solve easily x2+y2 =6xy then 2log (x-y) =?

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If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2 If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2
If x^2 + y^2 = 6xy find 2 log (x+y) - log xy If x^2 + y^2 = 6xy find 2 log (x+y) - log xy
x^2+y^2=6xy then prove that 2log(x+y) =logx+logy+3log2 x^2+y^2=6xy then prove that 2log(x+y) =logx+logy+3log2
If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2` If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2`
If x²+y²=6xy, then prove that 2log(x+y)=logx+logy+3log2 | Real numbers | logarithms If x²+y²=6xy, then prove that 2log(x+y)=logx+logy+3log2 | Real numbers | logarithms
Visual math proof x² - y² = (x + y)(x - y) Visual math proof x² - y² = (x + y)(x - y)
if x² + y² = 6xy prove that 2log(x+y) = logx + logy + 3log2 if x² + y² = 6xy prove that 2log(x+y) = logx + logy + 3log2
Factorise completely x² -xy - 2y² and 8x² -6xy -9y². Factorise completely x² -xy - 2y² and 8x² -6xy -9y².