If sigma r=0 to 5 11C(2r+1) /2r+2 = m/n, gcd(m,n)=1, then m-n = ,#iitjee2025

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If sigma r=0 to 5 11C(2r+1)/2r+2 = m/n, gcd(n,n)=1, then n-n is equal to If sigma r=0 to 5 11C(2r+1)/2r+2 = m/n, gcd(n,n)=1, then n-n is equal to
If ∑_(r=0)^5▒(_ ^11)C_(2r+1) /(2r+2)= m/n , gcd ( m, n) = 1 , then m – n is equal to If ∑_(r=0)^5▒(_ ^11)C_(2r+1) /(2r+2)= m/n , gcd ( m, n) = 1 , then m – n is equal to
If ∑ 11 C 2r+1/ 2r+2 = m/n , gcd(m, n) = 1, then m – n is equal to_____ If ∑ 11 C 2r+1/ 2r+2 = m/n , gcd(m, n) = 1, then m – n is equal to_____
If ∑r=0 to 5 (11C(2r+1))/(2r+2) = m/n ,gcd(m, n) =1 , then m−n is equal to If ∑r=0 to 5 (11C(2r+1))/(2r+2) = m/n ,gcd(m, n) =1 , then m−n is equal to
Let 𝐴={1,2,3,……,10} and 𝐵={𝑚/𝑛:𝑚,𝑛∈𝐴,𝑚𝑛 and " gcd(𝑚,𝑛)=1}Then n(B) is equal toJEE MAINS Let 𝐴={1,2,3,……,10} and 𝐵={𝑚/𝑛:𝑚,𝑛∈𝐴,𝑚𝑛 and " gcd(𝑚,𝑛)=1}Then n(B) is equal toJEE MAINS
The value sum r=0 to 5 11C2r+1/2r+2 ( JEE mains 22 Jan 2025 ( morning shift)) The value sum r=0 to 5 11C2r+1/2r+2 ( JEE mains 22 Jan 2025 ( morning shift))
If gcd (m,n) = 1 and 12-22+32-42+ (2023)2 = 1012m²n, to + (2021)2-(2022)² + || Let If gcd (m,n) = 1 and 12-22+32-42+ (2023)2 = 1012m²n, to + (2021)2-(2022)² + || Let's IQRA JEE
#If 〖11〗_(C_1 )/2+〖11〗_(C_2 )/3+⋯.+〖11〗_(C_9 )/10=n/m with gcd(m, n)=1, then n+m= #If 〖11〗_(C_1 )/2+〖11〗_(C_2 )/3+⋯.+〖11〗_(C_9 )/10=n/m with gcd(m, n)=1, then n+m=