11th Std Maths Example 2.36 Prove log 75/16 - 2 log 5/9 + log 32/243 = log 2

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11th maths Basic Algebra chapter 2 example 2.36 tn syllabus hiba maths 11th maths Basic Algebra chapter 2 example 2.36 tn syllabus hiba maths
Prove that \( \log \frac{75}{16}-2 \log \frac{5}{9}+\log \frac{32}{243}=\log 2 \) Prove that \( \log \frac{75}{16}-2 \log \frac{5}{9}+\log \frac{32}{243}=\log 2 \)
Simplify : log(75)/( 16) - 2 log ( 5)/(9)+log( 32)/(243) | 9 | CHAPTERWISE REVISION (STAGE 1) ... Simplify : log(75)/( 16) - 2 log ( 5)/(9)+log( 32)/(243) | 9 | CHAPTERWISE REVISION (STAGE 1) ...
Prove that log 75/16 - 2log5/9 + log 32/243 = log2 | Logarithmic Question Prove that log 75/16 - 2log5/9 + log 32/243 = log2 | Logarithmic Question
##11th maths example 2.36 log75/16 - 2log5/9 +log32/243=log2 என நிறுவுக ##11th maths example 2.36 log75/16 - 2log5/9 +log32/243=log2 என நிறுவுக
TN Class 11 Maths Basic Algebra Example 2.36 TN Class 11 Maths Basic Algebra Example 2.36
log 75/16 - 2 log 5/9 + log 32/243....reduce the following....Laws of logarithm #mirztuition log 75/16 - 2 log 5/9 + log 32/243....reduce the following....Laws of logarithm #mirztuition
Simplify `: log\ 75/16 - 2 log\ 5/9 + log\ 32/243` Simplify `: log\ 75/16 - 2 log\ 5/9 + log\ 32/243`