If alpha and beta be the roots of the equation x^2-64x+256=0 #quadratic #iit #shorts

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If alpha & beta be roots of x^2-64x+256 = 0 then value of || JEE 2020 If alpha & beta be roots of x^2-64x+256 = 0 then value of || JEE 2020
If alpha and beta be two roots of the equation x^2-64x+256=0.Then the value of [alpha^3/beta^5]^1/8+ If alpha and beta be two roots of the equation x^2-64x+256=0.Then the value of [alpha^3/beta^5]^1/8+
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+ Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/ Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/
If α and β be two roots of the equation x^2 – 64x + 256 =0. Then the value of (α^3/β^5)^(1/8) + (β^3 If α and β be two roots of the equation x^2 – 64x + 256 =0. Then the value of (α^3/β^5)^(1/8) + (β^3
If α and β be two roots of the equation x^2-64 x+256=0. Then the value of (α^3/β^5)^1 / 8+(β^3/α^... If α and β be two roots of the equation x^2-64 x+256=0. Then the value of (α^3/β^5)^1 / 8+(β^3/α^...
If α and β be two of x^2-64x+256=0. Then the values of (α^3/β^5 )^(1/8)+(β^3/α^5 )^(1/8) is If α and β be two of x^2-64x+256=0. Then the values of (α^3/β^5 )^(1/8)+(β^3/α^5 )^(1/8) is
If ∝ and β be two roots of the equation x² – 64x + 256 = 0. Then.. | Quadratic Equations | JEE Math If ∝ and β be two roots of the equation x² – 64x + 256 = 0. Then.. | Quadratic Equations | JEE Math