In the given figure, BC is the diameter Of the circle and ∠BAO = 60º Then ∠ADC is equal to –(a) 60°

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In the given figure, BC is a diameter of the circle and ∠BAO = 60°. Then ∠ADC is equal to :(a) 30° In the given figure, BC is a diameter of the circle and ∠BAO = 60°. Then ∠ADC is equal to :(a) 30°
In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to :(A) 30º (B) 45º In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to :(A) 30º (B) 45º
In figure, BC is a diameter of the circle and angleBAO=60^(@). Then, angleADCis equal to | 9 | ... In figure, BC is a diameter of the circle and angleBAO=60^(@). Then, angleADCis equal to | 9 | ...
In the given figure, \( \mathrm{BC} \) is the diameter of the circle and \( \angle \mathrm{BAO}=... In the given figure, \( \mathrm{BC} \) is the diameter of the circle and \( \angle \mathrm{BAO}=...
In figure, BC is a diameter of the circle and angleBAO=60^(@). Then, angleADCis equal to | 9 | ... In figure, BC is a diameter of the circle and angleBAO=60^(@). Then, angleADCis equal to | 9 | ...
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