Prove that: (2n+1)!/n! =2^n { 1.3.5... (2n-1) (2n + 1) }

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Prove that `((2n+1)!)/(n!)=2^n[1.3.5.....(2n-1).(2n+1)]` Prove that `((2n+1)!)/(n!)=2^n[1.3.5.....(2n-1).(2n+1)]`
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prove (2n)!/n! = [1.3.5....(2nāˆ’1)].2^n I class 11 I @deepakmittalmakesuexpert prove (2n)!/n! = [1.3.5....(2nāˆ’1)].2^n I class 11 I @deepakmittalmakesuexpert
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