Prove by the principle of mathematical induction: 1.3 + 3.5 + 5.7 + ... + (2n–1)(2n+1) = n(4n²+6n–1)

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prove by the principle of mathematical induction that 1.3+3.5+5.7+...+(2n-1)(2n+1)= (n(4n²+6n-1))/3 prove by the principle of mathematical induction that 1.3+3.5+5.7+...+(2n-1)(2n+1)= (n(4n²+6n-1))/3
Prove the following by the principle of induction |1.3+3.5+5.7+..+(2n-1)(2n+1)=n(4n^+6n-)/3 Prove the following by the principle of induction |1.3+3.5+5.7+..+(2n-1)(2n+1)=n(4n^+6n-)/3
`1.3+3.5+5.7+......+(2n-1)(2n+1)=(n(4n^2+6n-1))/3` `1.3+3.5+5.7+......+(2n-1)(2n+1)=(n(4n^2+6n-1))/3`
prove that 1.3 + 3.5 + 5.7 +…+ (2n–1) (2n+1) =n(4n²+6n-1)/3.|| Worldeez Academy prove that 1.3 + 3.5 + 5.7 +…+ (2n–1) (2n+1) =n(4n²+6n-1)/3.|| Worldeez Academy
4.1, 7 principle of mathematical induction 1.3+3.5+5.7+...+ (2n - 1)(2n + 1) =(n(4n ^ 2 + 6n - 1))/3 4.1, 7 principle of mathematical induction 1.3+3.5+5.7+...+ (2n - 1)(2n + 1) =(n(4n ^ 2 + 6n - 1))/3
1.3+3.5+5.7+...+(2n-1)(2n+1)=(1/3)n(4n^2+6n-1) #MathematicalInduction #Algebra L380 1.3+3.5+5.7+...+(2n-1)(2n+1)=(1/3)n(4n^2+6n-1) #MathematicalInduction #Algebra L380
1.3+3.5+5.7+..+(2n-1)(2n+1)=(1/3)n(4n^2+6n-1) #MathematicalInduction #Algebra L400 1.3+3.5+5.7+..+(2n-1)(2n+1)=(1/3)n(4n^2+6n-1) #MathematicalInduction #Algebra L400
Mathematical Induction| Class 11| Exercise 4.1 Mathematical Induction| Class 11| Exercise 4.1