Given, log 2=0.301 and log 3=0.477, then the number of digits before decimal in 3^12× 2^8 is (a) ...

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Given ,log2=0.301 and log3=0.477, then the number of digits before decimal in `3^12times2^8`is Given ,log2=0.301 and log3=0.477, then the number of digits before decimal in `3^12times2^8`is
Given that `log 2 =0.301,` find the number of digits before decimal in the solution to the equ Given that `log 2 =0.301,` find the number of digits before decimal in the solution to the equ
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If `log2=0.301 and log3=0.477`, find the number of digits in: `(3^15xx2^10)` If `log2=0.301 and log3=0.477`, find the number of digits in: `(3^15xx2^10)`
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