Define a relation R on the interval [0, π/2) by xRy if and only if (sec)^2 x- (tan)^2 y=1. Then R

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Define a relation R on the interval [0,┤ ├ π/2) by xRy if and only if 〖sec〗^2 x-〖tan〗^2 y=1. Then Define a relation R on the interval [0,┤ ├ π/2) by xRy if and only if 〖sec〗^2 x-〖tan〗^2 y=1. Then
Q) Define a relation 𝑅 on the interval [0,𝜋/2) by 𝑥𝑅𝑦 if and only if sec^2 𝑥−tan^2 𝑦=1. Then 𝑅 is : Q) Define a relation 𝑅 on the interval [0,𝜋/2) by 𝑥𝑅𝑦 if and only if sec^2 𝑥−tan^2 𝑦=1. Then 𝑅 is :
Define a relation R on the interval [0, π/2) by xRy if and only if (sec)^2 x- (tan)^2 y=1.Then R is Define a relation R on the interval [0, π/2) by xRy if and only if (sec)^2 x- (tan)^2 y=1.Then R is
Define a Relation R in interval sec^2x-tan^2y=1 | JEE MAINS 29 JAN 2025 SHIFT 1 | Mathematics Define a Relation R in interval sec^2x-tan^2y=1 | JEE MAINS 29 JAN 2025 SHIFT 1 | Mathematics
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Q.20. Assertion (A): The function 𝑓:𝑅− {(2𝑛+1)𝜋/2 :𝑛∈𝑍 }→ (−∞,−1]∪[1,∞) defined by f(x)= sec x is Q.20. Assertion (A): The function 𝑓:𝑅− {(2𝑛+1)𝜋/2 :𝑛∈𝑍 }→ (−∞,−1]∪[1,∞) defined by f(x)= sec x is
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