If a,b,c,d are in G.P., then the value of `(a-c)^2+(b-c)^2+(b-d)^2-(a-d)^2` is

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If \( a, b, c, d \) are in G.P., show that \[ (b-c)^{2}+(c-a)^{2}+(d-b)^{2}=(a-d)^{2} . \] If \( a, b, c, d \) are in G.P., show that \[ (b-c)^{2}+(c-a)^{2}+(d-b)^{2}=(a-d)^{2} . \]
If a,b,c,d be in G.P. show that `(b-c)^2+(c-a)^2+(d-b)^2=(a-d)^2.` If a,b,c,d be in G.P. show that `(b-c)^2+(c-a)^2+(d-b)^2=(a-d)^2.`
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If a,b,c,d be in G.P. show that `(b-c)^2+(c-a)^2+(d-b)^2=(a-d)^2.` If a,b,c,d be in G.P. show that `(b-c)^2+(c-a)^2+(d-b)^2=(a-d)^2.`
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If a,b,c,d………are in G.P., then show that (a-b)^2, (b-c)^2, (c-d)^2 are in G.P. | 12 | GP - FOR B... If a,b,c,d………are in G.P., then show that (a-b)^2, (b-c)^2, (c-d)^2 are in G.P. | 12 | GP - FOR B...
If a, b, c and d are in G.P. show that (a^2+b^2+c^2)(b^2+c^2+d^2)=(a b+b c+c d)^2 . a, b, c, d → ... If a, b, c and d are in G.P. show that (a^2+b^2+c^2)(b^2+c^2+d^2)=(a b+b c+c d)^2 . a, b, c, d → ...