Q) The value of (0.16)^(log_2.5 (1/3+1/3^2 +1/3^3 +…∞) ) JEE MAINS 2025 #relationandfunctions

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Q) The value of (0.16)^(log_2.5 (1/3+1/3^2 +1/3^3 +…∞) ) is equal to #jee2026 #jeemaths #maths Q) The value of (0.16)^(log_2.5 (1/3+1/3^2 +1/3^3 +…∞) ) is equal to #jee2026 #jeemaths #maths
The value of (0.16) log _2.5(1/3+1/3^2+1/3^3+…∞) equal to The value of (0.16) log _2.5(1/3+1/3^2+1/3^3+…∞) equal to
The value of `(0.16)^("log"_(0.25)((1)/(3) + (1)/(3^(2)) + (1)/(3^(3)) + …."to" oo))`, is The value of `(0.16)^("log"_(0.25)((1)/(3) + (1)/(3^(2)) + (1)/(3^(3)) + …."to" oo))`, is
The value of (0.16)^log(2.5)(1/3+1/3^2+1/3^3+…to∞) equal to __________ [3rd Sep, 1st Shift 2020] The value of (0.16)^log(2.5)(1/3+1/3^2+1/3^3+…to∞) equal to __________ [3rd Sep, 1st Shift 2020]
The value of \( (0.16) \) \( \log _{2.5}\left(\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^{3}}+\ldots... The value of \( (0.16) \) \( \log _{2.5}\left(\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^{3}}+\ldots...
The value of (0.16) log _2.5{1/3+1/3^2+…} is (a) 2 (b) 4 (c) 6 The value of (0.16) log _2.5{1/3+1/3^2+…} is (a) 2 (b) 4 (c) 6
How to solve log type Question/ #shorts #ytshorts How to solve log type Question/ #shorts #ytshorts
The value of (0.16)^(log_(2.5)((1)/(3) + (1)/(3^(2)) + (1)/(3^(3)) + ….to oo)), is | 12 | LOGARI... The value of (0.16)^(log_(2.5)((1)/(3) + (1)/(3^(2)) + (1)/(3^(3)) + ….to oo)), is | 12 | LOGARI...