PAB is a secant and PT is tangent to a circle. If PA:AB = 1:3 and PT = 6 cm, find the tangent of PB

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PAB is a secant and PT is tangent to a circle. If PA:AB = 1:3 and PT=6cm find the length of PB PAB is a secant and PT is tangent to a circle. If PA:AB = 1:3 and PT=6cm find the length of PB
In the given figure, PAB is a secant and PT is a tangent to the circle from P. If PT=8 cm, PA = 6CM In the given figure, PAB is a secant and PT is a tangent to the circle from P. If PT=8 cm, PA = 6CM
Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy
In the given figure PAB is a secant and PT is a tangent to the circle from P. If PT= 8 and PA=6 PB=x In the given figure PAB is a secant and PT is a tangent to the circle from P. If PT= 8 and PA=6 PB=x
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In the given figure, PAB is a secant and PT is a tangent to the circle from P. If PT=8 cm, PA = 6CM In the given figure, PAB is a secant and PT is a tangent to the circle from P. If PT=8 cm, PA = 6CM
In the given figure, O is the centre of the circle, PT is the tangent and PAB is the secant passes In the given figure, O is the centre of the circle, PT is the tangent and PAB is the secant passes
In the given figure,PAB is a secant, PT is a tangent to the circle.If PT=5cm and PA = 4 cm, find AB. In the given figure,PAB is a secant, PT is a tangent to the circle.If PT=5cm and PA = 4 cm, find AB.