`log a/(y-z)=log b/(z-x)=logc/(x-y), then a^xb^yc^z` is equal to

Tonton & Download Video Musik Gratis

🏠 Beranda
⬇ DOWNLOAD NOW
Kalau muncul iklan pop-up, tutup lalu klik tombol kembali

Download lagu `log a/(y-z)=log b/(z-x)=logc/(x-y), then a^xb^yc^z` is equal to secara gratis hanya untuk keperluan promosi. Dukung artis favorit kamu dengan membeli musik original di iTunes atau platform resmi lainnya.

🎬 Download Lagu Lainnya

If log a/y-z=log b/z-x=log c/x-y, then a b c= (a) a^x b^y c^z (b) a^y+z b^z+x c^x+y (c) 1 (d) All... If log a/y-z=log b/z-x=log c/x-y, then a b c= (a) a^x b^y c^z (b) a^y+z b^z+x c^x+y (c) 1 (d) All...
If logx/(y-z) = logy/(z-x) = logz/(x-y) then prove that xyz = 1 | IITJEE Foundation Maths If logx/(y-z) = logy/(z-x) = logz/(x-y) then prove that xyz = 1 | IITJEE Foundation Maths
If (loga)/(y-z)=(logb)/(z-x)=(logc)/(x-y) and a^(y^(2)+yz+z^(2))b^(z^(2)+zx+x^(2))c^(x^(2)+xy+y^... If (loga)/(y-z)=(logb)/(z-x)=(logc)/(x-y) and a^(y^(2)+yz+z^(2))b^(z^(2)+zx+x^(2))c^(x^(2)+xy+y^...
If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x. If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x.
If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1` If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1`
loga/(y-z)=logb/(z-x)=logc/(x-y) then value of abc= | 11 | LOGARITHMS | MATHS | OBJECTIVE RD SHA... loga/(y-z)=logb/(z-x)=logc/(x-y) then value of abc= | 11 | LOGARITHMS | MATHS | OBJECTIVE RD SHA...
If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A... If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A...
If x, y, z are positive real numbers prove that (yz)^(logy-logz)*(zx)^(logz-logx)*(xy)^(logx-logy)=1 If x, y, z are positive real numbers prove that (yz)^(logy-logz)*(zx)^(logz-logx)*(xy)^(logx-logy)=1