If `x=log_(2a) a,y=log_(3a) 2a ` and `z=log_(4a) 3a` then prove that `xyz+1=`

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If `log_(2a)a= X, log_(3a) 2a = y, and log_(4a) 3a` = z, then xyz-2yz is equal to If `log_(2a)a= X, log_(3a) 2a = y, and log_(4a) 3a` = z, then xyz-2yz is equal to