Q) If y = tan x + sec x prove that d^2 y/dx^2 = cos x / (1+ sin x )^2 CBSE 2026 Differentiation PYQ

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Q) ) If y = tan x + sec x then prove that d^2 y/dx^2 = cos x / (1+sin x)^2 CBSE PYQ 2023CBSE 2026 Q) ) If y = tan x + sec x then prove that d^2 y/dx^2 = cos x / (1+sin x)^2 CBSE PYQ 2023CBSE 2026
If y = tan x + sec x,then prove that (𝐝^𝟐 𝐲)/(𝐝𝐱^𝟐 )=𝐜𝐨𝐬𝐱/(𝟏−𝐬𝐢𝐧𝐱)^𝟐 #cbse2026 #m If y = tan x + sec x,then prove that (𝐝^𝟐 𝐲)/(𝐝𝐱^𝟐 )=𝐜𝐨𝐬𝐱/(𝟏−𝐬𝐢𝐧𝐱)^𝟐 #cbse2026 #m
If `y=tanx+secx` , prove that `(d^2y)/(dx^2)=(cosx)/((1-sinx)^2)` If `y=tanx+secx` , prove that `(d^2y)/(dx^2)=(cosx)/((1-sinx)^2)`
Q22 | If y=tan⁡x+sec⁡x prove that (d^2 y)/(dx^2 )=cos⁡x/(1-sin⁡x )^2 Q22 | If y=tan⁡x+sec⁡x prove that (d^2 y)/(dx^2 )=cos⁡x/(1-sin⁡x )^2
Calculus: Differentiation- If y = secx +tanx then show that d^2y/dx^2 = Cos x /( 1- sin x)^2. Calculus: Differentiation- If y = secx +tanx then show that d^2y/dx^2 = Cos x /( 1- sin x)^2.
Q12 | If y = tan ⁡x + sec⁡ x, then prove that d^2 y/dx^2 = cos ⁡x / (1-sin⁡x )^2 | CBSE Board 2023 Q12 | If y = tan ⁡x + sec⁡ x, then prove that d^2 y/dx^2 = cos ⁡x / (1-sin⁡x )^2 | CBSE Board 2023
If `y=(tan x+secx)`, prove that `(d^(2)y)/(dx^(2))=(cosx)/((1-sinx)^(2))` If `y=(tan x+secx)`, prove that `(d^(2)y)/(dx^(2))=(cosx)/((1-sinx)^(2))`
If y = tan x + sec x then prove that d²y/ dx² = cosx / (1-sinx)² CBSE 2026 Differentiation #maths If y = tan x + sec x then prove that d²y/ dx² = cosx / (1-sinx)² CBSE 2026 Differentiation #maths