The value of 6 + log 1/3√2 √4- 1/3√2 √4- 1/3√2 √4-1/3√2... to the base 3/2 is:| JEE Advanced Maths

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The value of ` 6 + log_(3/2) (1/(3sqrt2) sqrt(4 - 1/(3 sqrt2) sqrt(4 - ....))` The value of ` 6 + log_(3/2) (1/(3sqrt2) sqrt(4 - 1/(3 sqrt2) sqrt(4 - ....))`
The value of 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))... The value of 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))...
The value of \( 6+\log _{\frac{3}{2}}\left(\frac{1}{3 \sqrt{2}} \sqrt{4-\frac{1}{3 \sqrt{2}} \sq... The value of \( 6+\log _{\frac{3}{2}}\left(\frac{1}{3 \sqrt{2}} \sqrt{4-\frac{1}{3 \sqrt{2}} \sq...
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