If Sn​ denotes the sum of the first n terms of an A.P., prove that S30​=3(S20​−S10​)

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If Sn denotes the sum of first n terms of an AP, prove that S30=3[S20-S10] (CBSE 2015) 30/1/3 If Sn denotes the sum of first n terms of an AP, prove that S30=3[S20-S10] (CBSE 2015) 30/1/3
If Sn denotes the sum of the first n terms of an A.P., prove that S30 = 3(S20-S10). If Sn denotes the sum of the first n terms of an A.P., prove that S30 = 3(S20-S10).
If Sn denotes the sum of the first n terms of an A.P., prove that S30=3(S20 - S10). [CBSC 2014] If Sn denotes the sum of the first n terms of an A.P., prove that S30=3(S20 - S10). [CBSC 2014]
If Sn denotes the sum of the first n terms of an AP Then prove that- S30 = 3(S20 – S10) | AP If Sn denotes the sum of the first n terms of an AP Then prove that- S30 = 3(S20 – S10) | AP
☀️ Prove S 30 = 3 (S 20 - S 10) ☀️ Prove S 30 = 3 (S 20 - S 10)
Ques: Prove that:S30=3(S20-S10). Arithmetic Progression Class10 MLAggarwalSolutions Ques: Prove that:S30=3(S20-S10). Arithmetic Progression Class10 MLAggarwalSolutions
Let S denote sum of first n terms of an arithmetic progression.If S20 790 and S10 145 then S15-S5 is Let S denote sum of first n terms of an arithmetic progression.If S20 790 and S10 145 then S15-S5 is
😵‍💫 Prove S30=3x(S20-S10) for an A.P. 😵‍💫 Prove S30=3x(S20-S10) for an A.P.