Let a_1,a_2,a_3,…be in an A.P. such that ∑_(k=1)^12▒a_(2k-1) =-72/5 a_1,a_1≠0. If ∑_(k=1)^n▒a_k=0,

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Let \[{a_1},{a_2},{a_3},........\] be in an A.P. such that \[\sum\limits_{k = 1}^{12} {{a_{2k - 1}}} Let \[{a_1},{a_2},{a_3},........\] be in an A.P. such that \[\sum\limits_{k = 1}^{12} {{a_{2k - 1}}}
Let a1,a2,a3...be in an A.P. such that Σ a2k-1=-72/5 a1,a≠0.If Σak=0,then n is : Let a1,a2,a3...be in an A.P. such that Σ a2k-1=-72/5 a1,a≠0.If Σak=0,then n is :
Let a1, a2, a3... be in an AP. such that ∑ a2k-1=-72/5a1, a1≠0. If ∑ak=0, then n is: Let a1, a2, a3... be in an AP. such that ∑ a2k-1=-72/5a1, a1≠0. If ∑ak=0, then n is:
Q) Let 𝑎_1,𝑎_2,𝑎_3…. be in an A.P. such that ∑129_(𝑘=1)^12  𝑎_(2𝑘−1)=−72/5 𝑎_1,𝑎_1≠0 If ∑129 Q) Let 𝑎_1,𝑎_2,𝑎_3…. be in an A.P. such that ∑129_(𝑘=1)^12  𝑎_(2𝑘−1)=−72/5 𝑎_1,𝑎_1≠0 If ∑129
Let a1,a2,a3… in an AP and Sum_k=1 to 12 a_(2k-1) =(-72/5)a1 and Sum_k=1 to n a_k =0 |jeemain2025 Let a1,a2,a3… in an AP and Sum_k=1 to 12 a_(2k-1) =(-72/5)a1 and Sum_k=1 to n a_k =0 |jeemain2025
𝑎1, 𝑎2,… A.P.such that ∑_(k=1)^12▒a_(2k-1) = 1 72/5  a_1,a_1 ≠ 0, if ∑_(k=1)^n▒a_k =[JEE(M) 2/03/25 𝑎1, 𝑎2,… A.P.such that ∑_(k=1)^12▒a_(2k-1) = 1 72/5  a_1,a_1 ≠ 0, if ∑_(k=1)^n▒a_k =[JEE(M) 2/03/25
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