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For any natural number m is greater than 1, we have (2m)^2 + (m^2 – 1)^2 = (m^2 + 1)^2. So, 2m, m^2 For any natural number m is greater than 1, we have (2m)^2 + (m^2 – 1)^2 = (m^2 + 1)^2. So, 2m, m^2
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