Algebra | Finding abc given a + 3/b = 3 and b + 1/c = 1 [CAS #36]

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a3 + b3 + c3 - 3abc = ? (A Cube+ B Cube + C Cube- 3abc ) Formula of a cube plus b cube plus c cube a3 + b3 + c3 - 3abc = ? (A Cube+ B Cube + C Cube- 3abc ) Formula of a cube plus b cube plus c cube
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If (a+b)/c+(b+c)/a+(a+c)/b=3 and a+b+c=3, then 1/a+1/b+1/c=? #maths https://t.me/+N7U5eweSkfk1ZDdi If (a+b)/c+(b+c)/a+(a+c)/b=3 and a+b+c=3, then 1/a+1/b+1/c=? #maths https://t.me/+N7U5eweSkfk1ZDdi