Prove that 2a3+27c=9ab, if the roots of x3+ax2+bx+c=0 form an arithmetic sequence.

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If The Zeroes Of Polynomial X3 – AX2 + BX – C Are In AP Then Show That 2A3 – 9AB + 27C = 0 If The Zeroes Of Polynomial X3 – AX2 + BX – C Are In AP Then Show That 2A3 – 9AB + 27C = 0
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