If Cot theta equal to 7 by 8 Evaluate (i) (1+sin θ) (1-sin θ)/(1+cos θ)(1-cos θ) (ii) Cot²θ

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7. If cot θ =7/8 evaluate : (i) (1 sin )(1 sin ),(1 cos )(1 cos )+ θ − θ+ θ − θ(ii) cot2 θ 7. If cot θ =7/8 evaluate : (i) (1 sin )(1 sin ),(1 cos )(1 cos )+ θ − θ+ θ − θ(ii) cot2 θ
If cot theta is equal to 7 by 8 evaluate | Trigonometry If cot theta is equal to 7 by 8 evaluate | Trigonometry
If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ. If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ.
If cot θ= 7/8, evaluate (i) (1+ sinθ)(1- sinθ)/(1+cosθ )(1- cosθ ), (ii) cot²θ, class 10maths NCERT If cot θ= 7/8, evaluate (i) (1+ sinθ)(1- sinθ)/(1+cosθ )(1- cosθ ), (ii) cot²θ, class 10maths NCERT
Basic math sample paper solutions Class 10 | Q.24 | If cot theta=7/8 evaluate (1+sin theta)(1-sin ) Basic math sample paper solutions Class 10 | Q.24 | If cot theta=7/8 evaluate (1+sin theta)(1-sin )
If cot θ = 7/8, evaluate:(i) (1 + sin θ)(1 - sin θ) / (1 + cos θ)(1 - cos θ)(ii) cot²θ If cot θ = 7/8, evaluate:(i) (1 + sin θ)(1 - sin θ) / (1 + cos θ)(1 - cos θ)(ii) cot²θ
if 𝐶𝑜𝑡 θ = 15/8, θ is an acute angle, find (1−𝑐𝑜𝑠θ)(2+2𝑐𝑜𝑠θ)/(2−2𝑠𝑖𝑛θ)(1+𝑠𝑖𝑛θ) if 𝐶𝑜𝑡 θ = 15/8, θ is an acute angle, find (1−𝑐𝑜𝑠θ)(2+2𝑐𝑜𝑠θ)/(2−2𝑠𝑖𝑛θ)(1+𝑠𝑖𝑛θ)
If `cot theta = 7/8`, evaluate: (i) `((1+sin theta)(1-sin theta))/ | Class 10 Maths | Doubtnut If `cot theta = 7/8`, evaluate: (i) `((1+sin theta)(1-sin theta))/ | Class 10 Maths | Doubtnut