NCERT X Ex 8.1 Q7 If cotθ=7/8, evaluate (i) (1+sinθ)(1-sinθ)÷(1+cosθ)(1-cosθ) (ii) cot²θ

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If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ. If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ.
Class 10 | Ex 8.1 Q7 | Trigonometry | Chapter 8 NCERT | If cot θ = 7/8, evaluate:(i) (1+sinθ)... Class 10 | Ex 8.1 Q7 | Trigonometry | Chapter 8 NCERT | If cot θ = 7/8, evaluate:(i) (1+sinθ)...
If cot θ =7/8 evaluate : (i) (1+ sinθ )(1- sinθ )/(1+ cosθ )(1 -cosθ ) ,(ii) cot2 θ If cot θ =7/8 evaluate : (i) (1+ sinθ )(1- sinθ )/(1+ cosθ )(1 -cosθ ) ,(ii) cot2 θ
If Cot theta equal to 7 by 8 Evaluate (i) (1+sin θ) (1-sin θ)/(1+cos θ)(1-cos θ) (ii) Cot²θ If Cot theta equal to 7 by 8 Evaluate (i) (1+sin θ) (1-sin θ)/(1+cos θ)(1-cos θ) (ii) Cot²θ
Question no.7 || Trigonometry || Exercise - 8.1 || NCERT || Class 10 Question no.7 || Trigonometry || Exercise - 8.1 || NCERT || Class 10
if cot theta is equal to 7 by 8 then find 1 + sin theta upon 1 + cos theta if cot theta is equal to 7 by 8 then find 1 + sin theta upon 1 + cos theta
If `cot theta = 7/8`, evaluate: (i) `((1+sin theta)(1-sin theta))/ | Class 10 Maths | Doubtnut If `cot theta = 7/8`, evaluate: (i) `((1+sin theta)(1-sin theta))/ | Class 10 Maths | Doubtnut
If cotθ=15/8, then evalute: (2+2sinθ)(1-sinθ)/(1+cosθ)(2-2cosθ) If cotθ=15/8, then evalute: (2+2sinθ)(1-sinθ)/(1+cosθ)(2-2cosθ)