If lim x--0 (3+αsinx + βcosx+ ln(1-x))/3 tan^2 x =1/2 then 2α - β is equal to: JEE Mains 2024 27 jan

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If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025 #limits If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025 #limits
If lim x to 0 3+alpha sin x+beta cos x+log(1-x)/3|JEE|Main|2024|session 1|27 Feb 2024| Shift 2|NTA If lim x to 0 3+alpha sin x+beta cos x+log(1-x)/3|JEE|Main|2024|session 1|27 Feb 2024| Shift 2|NTA
If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025 #limits If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025 #limits
JEE Main 2025:For α,β,γ∈R, if lim(x→0) x² sin αx +(γ-1)e^x² / sin2x -βx = 3, then β+γ-α is equal to: JEE Main 2025:For α,β,γ∈R, if lim(x→0) x² sin αx +(γ-1)e^x² / sin2x -βx = 3, then β+γ-α is equal to:
JEE Main 2022: Let β = lim(x→0) αx-(e³ˣ-1) /αx(e³ˣ-1) for some α∈R. Then the value of α+β is: JEE Main 2022: Let β = lim(x→0) αx-(e³ˣ-1) /αx(e³ˣ-1) for some α∈R. Then the value of α+β is:
Q) If a=lim(x→0) (√(1+√(1+x^4 )) −√2)/x^4 and 𝑏=lim(𝑥→0) (sin^2 𝑥)/(√2−√(1+cos𝑥)), then the va Q) If a=lim(x→0) (√(1+√(1+x^4 )) −√2)/x^4 and 𝑏=lim(𝑥→0) (sin^2 𝑥)/(√2−√(1+cos𝑥)), then the va
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JEE Main 2022: If lim(x→0) αeˣ + βe⁻ˣ + γ sinx / x sin²x = 2/3, where α,β,γ∈R, then which of the JEE Main 2022: If lim(x→0) αeˣ + βe⁻ˣ + γ sinx / x sin²x = 2/3, where α,β,γ∈R, then which of the