Class 11 || Maths || Trigonometric Functions || If tanA-tanB=x and cotB-cotA=y, cot(A-B) = 1/x+1/y

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If tanA - tanB = x and cotB - cotA = y then cot (A-B) is equal to (a) 1/y-1/x (b) 1/x-1/y (c) 1/x+ If tanA - tanB = x and cotB - cotA = y then cot (A-B) is equal to (a) 1/y-1/x (b) 1/x-1/y (c) 1/x+
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Trigonometric Identities Trigonometric Identities
If tanA-tanB=x and cotB-cotA=y, then cot(A-B) = ? If tanA-tanB=x and cotB-cotA=y, then cot(A-B) = ?
Trigonometric Graphs Trigonometric Graphs
(i) If tanA-tan B=x andcot B- cot A=y. Prove that cot(A-B)=1/x + 1/y.(ii) If 2 cos A = x+1/x, 2 ... (i) If tanA-tan B=x andcot B- cot A=y. Prove that cot(A-B)=1/x + 1/y.(ii) If 2 cos A = x+1/x, 2 ...
If `tanA-tanB=x a n dcotB-cotA=y ,` prove that `cot(A-B)=1/x+1/y` If `tanA-tanB=x a n dcotB-cotA=y ,` prove that `cot(A-B)=1/x+1/y`
(cotA + tanB)/(cotB + tanA) = cotAtanB Trigonometric Identity (cotA + tanB)/(cotB + tanA) = cotAtanB Trigonometric Identity