Prove Cot A Cot B + Cot B Cot C + Cot A Cot C = 1 if A+B+C = π.

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Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1) Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1)
Prove that cotB cotC + cotC cotA + cotA cotB = 1 Prove that cotB cotC + cotC cotA + cotA cotB = 1
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Show that cot(A-B) = (1+ cotA cotB)/(cotB -cotA). if cotA =½, cotB =2 and cotC =3 then cot(A-B-C)=3. Show that cot(A-B) = (1+ cotA cotB)/(cotB -cotA). if cotA =½, cotB =2 and cotC =3 then cot(A-B-C)=3.
43Trigonometry If A + B + C = 90 thenshowthat Cot A + Cot B + Cot C = Cot A.Cot B.Cot C 43Trigonometry If A + B + C = 90 thenshowthat Cot A + Cot B + Cot C = Cot A.Cot B.Cot C
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Proof of Cot(A–B)=(CotA.CotB+1)/(CotB–CotA). Proof of Cot(A–B)=(CotA.CotB+1)/(CotB–CotA).