If (9^n×3^2×3^n - 27^n)/(3^3m×2^3)=1/27, Prove that m-n=1 /Number System / RD Sharma / Class 9 Maths

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If 9^n × 3^2 × 3^n - 27^n / 3^3m × 2^3 = 1/27, prove that m - n = 1. If 9^n × 3^2 × 3^n - 27^n / 3^3m × 2^3 = 1/27, prove that m - n = 1.
If [9^n×3²×[3^(-n/2)]^(-2)-(27)^n]/[3^(3m)×2³]=1/27. prove that m-n=1||Number System||(ch-1,class-9) If [9^n×3²×[3^(-n/2)]^(-2)-(27)^n]/[3^(3m)×2³]=1/27. prove that m-n=1||Number System||(ch-1,class-9)
[9^n × 3^2 × ( 3^-n/2)^-2 - ( 27)^n] / 3^3m×2^3 = 1/27, prove that m - n = 1, [9^n × 3^2 × ( 3^-n/2)^-2 - ( 27)^n] / 3^3m×2^3 = 1/27, prove that m - n = 1,