Find the values of ab+bc+ca, when a²+b²+c²=56 and a+b+c=12||a²+b²+c²=12 and a+b+c=5

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. If a² + b² + c² + 216 = 12(a + b - 2c), then 𝑎𝑏 − 𝑏𝑐 − 𝑐𝑎 is: SSC CGL 20/8/2021 . If a² + b² + c² + 216 = 12(a + b - 2c), then 𝑎𝑏 − 𝑏𝑐 − 𝑐𝑎 is: SSC CGL 20/8/2021
Mathematics Solution "a+b+c=15, a²+b²+c²=83, ab+bc+ca=?" Mathematics Solution "a+b+c=15, a²+b²+c²=83, ab+bc+ca=?"
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