The number of points of discontinuity of the function f(x)=[x^2/2]-[√x],x∈[0,4], where [•] denotes

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IIT-JEE MAINS 2025 april // Number of points of discontinuity of the function f(x)=[x^2/2]-[√x], IIT-JEE MAINS 2025 april // Number of points of discontinuity of the function f(x)=[x^2/2]-[√x],
The Number Of Points Of Discontinuity Of The Function f(x)=[x²/2]-[√x],x∈[0,4],Where [.] The Number Of Points Of Discontinuity Of The Function f(x)=[x²/2]-[√x],x∈[0,4],Where [.]
The number of points of discontinuity of the function f(x) = ⌊x²/2⌋ − ⌊√x⌋, x ∈ [0, 4], where ⌊ ⌋ .. The number of points of discontinuity of the function f(x) = ⌊x²/2⌋ − ⌊√x⌋, x ∈ [0, 4], where ⌊ ⌋ ..
No. of points of discontinuity of `[ 2 x^3 - 5]` in [1,2] is No. of points of discontinuity of `[ 2 x^3 - 5]` in [1,2] is
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Determine the discontinuity of the function Determine the discontinuity of the function