The area bounded by the curve `y = sin^(2) x, 0 le x le pi/2`, X axis and the line `x = pi/2` is

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The area bounded by curve y=sin x, x-axis and ordinates x=0 x=pi/2 Application Integrals|MCQ|BITSAT The area bounded by curve y=sin x, x-axis and ordinates x=0 x=pi/2 Application Integrals|MCQ|BITSAT
Area bounded by the curve `y=sin^(2)x` and lines `x=(pi)/(2),x=pi` and X-axis is Area bounded by the curve `y=sin^(2)x` and lines `x=(pi)/(2),x=pi` and X-axis is
The area bounded by the y-axis, y=cos x and y=sin x when 0 ≤ x ≤π/2 is : (A) 2(√(2)-1) (B) √(2)-1... The area bounded by the y-axis, y=cos x and y=sin x when 0 ≤ x ≤π/2 is : (A) 2(√(2)-1) (B) √(2)-1...
The area bounded by the curve `y =|cos x-sinx|, 0 lt=x lt=pi/2` and above x-axis is The area bounded by the curve `y =|cos x-sinx|, 0 lt=x lt=pi/2` and above x-axis is
Area enclosed by the curve `y = sin^(2)x`, the X-axis and the lines `x=0, x=pi//2` is Area enclosed by the curve `y = sin^(2)x`, the X-axis and the lines `x=0, x=pi//2` is
Area bounded by curve `y=sinx`, whit x-axis, when x varies from 0 to `(pi)/(2)` is :- Area bounded by curve `y=sinx`, whit x-axis, when x varies from 0 to `(pi)/(2)` is :-
y = sin x, y = sin 2x, x=0, x=pi/2 y = sin x, y = sin 2x, x=0, x=pi/2
Find the area of the region enclosed by the given curves .y=sinx ,y=cosx , x=0 , x=(pi)/(2) | 12... Find the area of the region enclosed by the given curves .y=sinx ,y=cosx , x=0 , x=(pi)/(2) | 12...