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![∫(x+((x+…)/(1+…)))/(1+((x+…)/(1+…)))dx [1,3] MIT Integration Bee 2024, Qualifying Exam, Question 20.](https://i.ytimg.com/vi/A9-26CTZm98/hq720_2.jpg?sqp=-oaymwE9COgCEMoBSFryq4qpAy8IARUAAAAAGAAlAADIQj0AgKJDeAHwAQH4Ac4FgAKACooCDAgAEAEYYiBlKD8wDw==&rs=AOn4CLAWzwXpmGtNwqTGuP4DSglVjDMjfQ)
∫(x+((x+…)/(1+…)))/(1+((x+…)/(1+…)))dx [1,3] MIT Integration Bee 2024, Qualifying Exam, Question 20.
∫x⁴/(3 - 6x + 6x² - 4x³ + 2x⁴) dx = ?? MIT Integration Bee 2024, Qualifying Exam, Question 19.
![∫1/(x + 1 + 2√x)² dx [0, ∞] MIT Integration Bee 2025, Regular Season, Problem 1 #mitintegrationbee](https://i.ytimg.com/vi/NduCO-GSVBY/hq720_2.jpg?sqp=-oaymwE9COgCEMoBSFryq4qpAy8IARUAAAAAGAAlAADIQj0AgKJDeAHwAQH4Ac4FgAKACooCDAgAEAEYZCBlKD8wDw==&rs=AOn4CLDG42H-Dc6kMlEd7Wy3iksxsiJM7w)
∫1/(x + 1 + 2√x)² dx [0, ∞] MIT Integration Bee 2025, Regular Season, Problem 1 #mitintegrationbee
MIT Integration Bee Qualifying Exam Problem #1