JEE Mains PYQ | Definite Integration | Let f(x)+2f(1/x)=x^2+5 and 2g(x)−3g(1/2)=x If α=∫_1^2▒f(x) 🔥

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Q) Let 𝑓(𝑥)+2𝑓(1/𝑥)=𝑥^2+5 and 2𝑔(𝑥)−3𝑔(1/2)=𝑥 . If 𝛼=∫_1^2 𝑓(𝑥)𝑑𝑥, and 𝛽=∫_1^2 𝑔(𝑥)𝑑𝑥, the Q) Let 𝑓(𝑥)+2𝑓(1/𝑥)=𝑥^2+5 and 2𝑔(𝑥)−3𝑔(1/2)=𝑥 . If 𝛼=∫_1^2 𝑓(𝑥)𝑑𝑥, and 𝛽=∫_1^2 𝑔(𝑥)𝑑𝑥, the
Let f(x)+2f(1/x)=x^2+5 and 2g(x)-3g(1/2)=x,x 0. If α=∫_1^2 f(x)dx, and β=∫_1^2 " " g(x)dx #jeemain Let f(x)+2f(1/x)=x^2+5 and 2g(x)-3g(1/2)=x,x 0. If α=∫_1^2 f(x)dx, and β=∫_1^2 " " g(x)dx #jeemain
Let 𝑓(𝑥)+2𝑓(1/𝑥)=𝑥^2+5 and 2𝑔(𝑥)−3𝑔(1/2)=𝑥 . If 𝛼=∫_1^2 𝑓(𝑥)𝑑𝑥, and 𝛽=∫_1^2 𝑔(𝑥)𝑑𝑥, the Let 𝑓(𝑥)+2𝑓(1/𝑥)=𝑥^2+5 and 2𝑔(𝑥)−3𝑔(1/2)=𝑥 . If 𝛼=∫_1^2 𝑓(𝑥)𝑑𝑥, and 𝛽=∫_1^2 𝑔(𝑥)𝑑𝑥, the
Let f(x)+2f(1/x)=x²+5 and 2g(x)-3g(1/2)=x,x›0.If α=∫ f(x) dx,and β=∫ g(x) dx,then the value of 9α+β Let f(x)+2f(1/x)=x²+5 and 2g(x)-3g(1/2)=x,x›0.If α=∫ f(x) dx,and β=∫ g(x) dx,then the value of 9α+β
JEE MMAIN 2026 ( L 5 ) Definite Integral ( Queen Property ) JEE MAIN PYQ 2025 - 2012 #jee2026 JEE MMAIN 2026 ( L 5 ) Definite Integral ( Queen Property ) JEE MAIN PYQ 2025 - 2012 #jee2026
Let f(x)+2f(1/x)=x^2+5 and 2g(x)-3g(1/2)=x. If a=Integral of f(x) from 1 to 2 and B=Integral of g(x) Let f(x)+2f(1/x)=x^2+5 and 2g(x)-3g(1/2)=x. If a=Integral of f(x) from 1 to 2 and B=Integral of g(x)
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Let f(x)+2 f(1/x)=x²+5 and 2g(x)-3g(1/2)=x, if α=∫ f(x)dx and β=∫ g(x)dx, then the value of 9α+β is Let f(x)+2 f(1/x)=x²+5 and 2g(x)-3g(1/2)=x, if α=∫ f(x)dx and β=∫ g(x)dx, then the value of 9α+β is