6#Find the other end of the diameter of the circle x² + y²–8x–8y+27=0 if one end of it is (2,3)

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FIND THE OTHER END OF THE DIAMETER X^2+Y^2-8X-8Y-27=0 ONE END IS (2,3) FIND THE OTHER END OF THE DIAMETER X^2+Y^2-8X-8Y-27=0 ONE END IS (2,3)
find the other end of the diameter of the circle x^2+y^2-8x-8y+27=0. if one end of it is (2,3) find the other end of the diameter of the circle x^2+y^2-8x-8y+27=0. if one end of it is (2,3)
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Shortcut to find the other end of the diameter of a circle if one end is given Shortcut to find the other end of the diameter of a circle if one end is given