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`sin^(-1)(1-x)-2sin^(-1)x=pi/2` , then x is equal to (A) `0,1/2` (B) `1,1/2` (C) 0 (D) `1/2`...
sin -1 ( 1-x ) - 2sin -1 x = π/2 then x =
'sin^-1(1-x)-2sin^-1(x)=pi/2' || 'sin^-1(1-x)-2 sin^-1x=π/2' || 'sin-1(1-x)-2 sin-1x=pi/2' then x is
'sin^-1(1-x)-2sin^-1(x)=pi/2' || 'sin^-1(1-x)-2 sin^-1x=π/2' || 'sin-1(1-x)-2 sin-1x=pi/2' then x is
Solve for x: sin^(-1)(1-x)-2sin^(-1)x=pi/2,#themathsgurudev,CLASS12, Inverse Trigonometric functions
sin inverse 1 - x - 2 sin inverse x is equal to pi by 2
sin ^-1(1-x)-2 sin ^-1 x=π/2, then x is equal to (A) 0, 1/2 (B) 1, 1/2 (C) 0 (D) 1/2 sin ^-1(1-x)...
Solve `2sin^(-1)x+sin^(-1)(1-x)=pi/2`