(NUMBER THEORY) Lecture 30: gcd(ka,kb)=mod k gcd(a,b)

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30. Properties of gcd | gcd is unique | gcd⁡(𝑘𝑎,𝑘𝑏)=|𝑘| gcd⁡(𝑎,𝑏) | gcd⁡(𝑎,𝑏)=𝑑⇔gcd⁡(𝑎/𝑑,𝑏/𝑑)=1 30. Properties of gcd | gcd is unique | gcd⁡(𝑘𝑎,𝑘𝑏)=|𝑘| gcd⁡(𝑎,𝑏) | gcd⁡(𝑎,𝑏)=𝑑⇔gcd⁡(𝑎/𝑑,𝑏/𝑑)=1
Number Theory || Theorem If k is positive integers then gcd (ka,kb) = k gcd(a,b) || 2.4 Number Theory || Theorem If k is positive integers then gcd (ka,kb) = k gcd(a,b) || 2.4
||Lecture#25||If k≥0 then prove that gcd(ka,kb)=kgcd(a,b)||@PRECIOUS LINES || ||Lecture#25||If k≥0 then prove that gcd(ka,kb)=kgcd(a,b)||@PRECIOUS LINES ||
Prove that gcd(ka,kb)=k.gcd(a,b). Prove that gcd(ka,kb)=k.gcd(a,b).
Prove that gcd(Ka,Kb)=K.gcd(a,b) in Number Theory Lecture 6 Prove that gcd(Ka,Kb)=K.gcd(a,b) in Number Theory Lecture 6
#Theorem: GCD (ka,kb)=|k|GCD(a,b) Proof//if k is positive then show that (ka,kb)=k(a,b)*** #Theorem: GCD (ka,kb)=|k|GCD(a,b) Proof//if k is positive then show that (ka,kb)=k(a,b)***
The Greatest Common Divisor -- Number Theory 4 The Greatest Common Divisor -- Number Theory 4
(NUMBER THEORY) Lecture 22: If k is positive integer then gcd(Ka,kb) = k gcd(a,b) (NUMBER THEORY) Lecture 22: If k is positive integer then gcd(Ka,kb) = k gcd(a,b)