If summation r=1 to infinity tan^-1(1/2r^2) =t, then tan t is ? Jee test series Inverse Trigonometry

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JEE Main 2021 Solution | SUM(t=1 to infinity) tan^-1(6^r/{2^(2r+1)+3^(2r+1)}) #JEEMAIN2021 JEE Main 2021 Solution | SUM(t=1 to infinity) tan^-1(6^r/{2^(2r+1)+3^(2r+1)}) #JEEMAIN2021
Sigma_(r=1)^(infty)tan^(-1)(1)/(2r^(2))=t then tan t is equal to | 12 | INVERSE TRIGONOMETRIC FU... Sigma_(r=1)^(infty)tan^(-1)(1)/(2r^(2))=t then tan t is equal to | 12 | INVERSE TRIGONOMETRIC FU...
If sum_(r=1)^(50)tan^(-1)1/(2r^2)=p,then the value of tan p is: | CLASS 12 | JEE MAINS 2021 | M... If sum_(r=1)^(50)tan^(-1)1/(2r^2)=p,then the value of tan p is: | CLASS 12 | JEE MAINS 2021 | M...
Limit where n tends to ♾️ tan {Summation of r=1 to n tan^-1 (1/1+r+r^2)} is equal to: Limit where n tends to ♾️ tan {Summation of r=1 to n tan^-1 (1/1+r+r^2)} is equal to:
Let Sk = Summation of r=1 to k tan^-1 (6^r/ 2^2r+1 + 3^2r+1). Then Lim k tends to infinity Sk = ? Let Sk = Summation of r=1 to k tan^-1 (6^r/ 2^2r+1 + 3^2r+1). Then Lim k tends to infinity Sk = ?
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`sum_(r=1) ^n tan^-1 (2^(r-1) / (1+ 2^(2r-1))) ` is equal to `sum_(r=1) ^n tan^-1 (2^(r-1) / (1+ 2^(2r-1))) ` is equal to
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