If `sinx+cosecx=2`, then, for all `n in N`, the value of: `sin^nx+cosec^nx=` (a) `2` (b) `2^n` (c)

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If `sinx+cosecx =2` then `sin^nx+cosec^nx=` If `sinx+cosecx =2` then `sin^nx+cosec^nx=`
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