IIT JEE LOGARITHM The least value of the expression `2(log)_(10)x-(log)_x(0.01)dot` for `x >1...

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The least value of the expression 2(log)_(10)x-(log)_x(0. 01), for x >,1, is (1980, 2M) (a) 1... The least value of the expression 2(log)_(10)x-(log)_x(0. 01), for x >,1, is (1980, 2M) (a) 1...
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solve for x: `2log_10x-log_x(0.01)=5` solve for x: `2log_10x-log_x(0.01)=5`
If `n=1999!` then `sum_(x=1)^(1999) log_n x=` If `n=1999!` then `sum_(x=1)^(1999) log_n x=`
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