If (x - iy)¹/³= a - ib then prove that x/a + y/b = 4(a² - b²) complex number #intermediate #inter

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(x-iy)⅓ = a-ib ; Complex Numbers @EAG (x-iy)⅓ = a-ib ; Complex Numbers @EAG
lf (x + iy)^1/3 = a + ib then x/a + y/b =4(a^2-b^2) lf (x + iy)^1/3 = a + ib then x/a + y/b =4(a^2-b^2)
lf (x + iy)^1/3 = a + ib then x/a + y/b = lf (x + iy)^1/3 = a + ib then x/a + y/b =
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