Prove that x^(logy-logz).y^(logz-logx).z^(logx-logy)=1 civil first semester imp Quection @enote #vir

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prove that `x^(logy-logz).y^(logz-logx).z^(logx-logy)=1` prove that `x^(logy-logz).y^(logz-logx).z^(logx-logy)=1`
Prove that x^(logy-logz).y^(logz-logx).z^(logx-logy)=1 | CLASS 12 | LOGARITHM | MATHS | Doubtnut Prove that x^(logy-logz).y^(logz-logx).z^(logx-logy)=1 | CLASS 12 | LOGARITHM | MATHS | Doubtnut
Show that : (yz)^(logy-logz)×(zx)^(logz-logx)×(xy)^(logx-logy) = 1 Show that : (yz)^(logy-logz)×(zx)^(logz-logx)×(xy)^(logx-logy) = 1
If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x. If x(y+z-x)/logx=y(z+x-y)/logy=z(x+y-z)/logz then prove that x^y.y^x=z^y.y^z=x^z.z^x.
Prove the following identities. (i) log(xyz) = log x + log y + log z (ii) loga(b) = 1/logb(a) Prove the following identities. (i) log(xyz) = log x + log y + log z (ii) loga(b) = 1/logb(a)
x^(log y-log z)*y^(log z-log x)*z^(log x-log y) simplify x^(log y-log z)*y^(log z-log x)*z^(log x-log y) simplify
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