If \( X=\left\{8^{n}-7 n-1 / n \in N\right\} \) and \( Y=\{49(n-1) / n \in N\} \), then (A) \( X...

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If \( X=\left\{8^{n}-7 n-1 / n \in N\right\} \) and \( Y=\{49(n-1) ... If \( X=\left\{8^{n}-7 n-1 / n \in N\right\} \) and \( Y=\{49(n-1) ...
If \( X=\left\{8^{n}-7 n-1: n \in N\right\} \) and \( Y=\{49(n-1): n \in N\} \), then.... If \( X=\left\{8^{n}-7 n-1: n \in N\right\} \) and \( Y=\{49(n-1): n \in N\} \), then....
If \( X=\left\{8^{n}-7 n-1 / n \in N\right\} \) and \( Y=\{49(n-1) / n \in N\} \), then If \( X=\left\{8^{n}-7 n-1 / n \in N\right\} \) and \( Y=\{49(n-1) / n \in N\} \), then
If \( X=\left\{8^{n}-7 n-1: n \in N\right\} \) and \( Y=\{49(n-1): ... If \( X=\left\{8^{n}-7 n-1: n \in N\right\} \) and \( Y=\{49(n-1): ...
If X={8^(n)-7n-1,n in N} and Y={49(n-1):n inN},then prove that X sube Y. | 11 | SETS | MATHS | N... If X={8^(n)-7n-1,n in N} and Y={49(n-1):n inN},then prove that X sube Y. | 11 | SETS | MATHS | N...
If A= {8^n-7n-1:nāˆˆN} and B= {49 (n-1):nāˆˆN} then If A= {8^n-7n-1:nāˆˆN} and B= {49 (n-1):nāˆˆN} then
If X = {8n ā€“ 7n ā€“ 1 | n Ǝ N} and Y = {49n ā€“ 49 | n Ǝ N}. Then(A) X ƌ Y (B) Y ƌ X (C) X = Y (D) X Ƈ Y If X = {8n ā€“ 7n ā€“ 1 | n Ǝ N} and Y = {49n ā€“ 49 | n Ǝ N}. Then(A) X ƌ Y (B) Y ƌ X (C) X = Y (D) X Ƈ Y
If X = {8^n - 7n - 1: n āˆˆ N} and Y = (49n - 49 : n āˆˆ N). then If X = {8^n - 7n - 1: n āˆˆ N} and Y = (49n - 49 : n āˆˆ N). then