If f(x)=∫(5x^8+7x^6)/(x^2+1+2x^7)^2 dx,(x≥0) and f(0) = 0, then the value of f(1) is

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If f(x)= Integral of 5x^8+7x^6/(x^2+1+2x^7)^2 dx (x 0), f(0)=0 & f(1)=1/K, then the value of K is If f(x)= Integral of 5x^8+7x^6/(x^2+1+2x^7)^2 dx (x 0), f(0)=0 & f(1)=1/K, then the value of K is
If f(x)=∫▒(5x^8+7x^6)/(x^2+1+2x^7 )^2 dx,(x≥0), and f(0)=0, then the value of f(1) is: If f(x)=∫▒(5x^8+7x^6)/(x^2+1+2x^7 )^2 dx,(x≥0), and f(0)=0, then the value of f(1) is:
If f(x)=∫▒(5x^8+7x^6)/〖(x^2+1+2x^7)〗^2 dx,(x≥0) and f(0) = 0, then the value of f(1) is If f(x)=∫▒(5x^8+7x^6)/〖(x^2+1+2x^7)〗^2 dx,(x≥0) and f(0) = 0, then the value of f(1) is
JEE MAIN 2021 SOLUTION - f(x) = integrate [(5x^8 + 7x^6)/(2x^7+x^2+1)]dx, f(0)=0 f(1)=1/k Find k JEE MAIN 2021 SOLUTION - f(x) = integrate [(5x^8 + 7x^6)/(2x^7+x^2+1)]dx, f(0)=0 f(1)=1/k Find k
If `f(x) = int(5x^(8)+7x^(6))/((x^(2)+1+2x^(7))^(2))dx, (x ge 0)`, and f(0) = 0, then If `f(x) = int(5x^(8)+7x^(6))/((x^(2)+1+2x^(7))^(2))dx, (x ge 0)`, and f(0) = 0, then