Q) The value of (1×2^2+2×3^2+…+100×(101)^2)/(1^2×2+2^2×3+…+100^2×101) # #jeemains #maths #class

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Q) The value of (1×2^2+2×3^2+…+100×(101)^2)/(1^2×2+2^2×3+…+100^2×101) # #jeemains #maths #class Q) The value of (1×2^2+2×3^2+…+100×(101)^2)/(1^2×2+2^2×3+…+100^2×101) # #jeemains #maths #class
The value of 1*2^2+2*3^2+100*101^2/1^2*2+2^2*3+.100^2*101 |JEE|Main|2024|session 2|4 April| Shift 2 The value of 1*2^2+2*3^2+100*101^2/1^2*2+2^2*3+.100^2*101 |JEE|Main|2024|session 2|4 April| Shift 2
The value of 1×2^2+2×3^2+…+100×(101)^2/1^2×2+2^2×3+…+100^2×101 is The value of 1×2^2+2×3^2+…+100×(101)^2/1^2×2+2^2×3+…+100^2×101 is
The value of 1x2²+2x32 +...+100×(101) 2 12x2+22x3+...+1002 ×101 is || Let The value of 1x2²+2x32 +...+100×(101) 2 12x2+22x3+...+1002 ×101 is || Let's IQRA JEE
Value of (1.2squ+2.3squ+...+100.101Sq)/(1squ.2+2squ.3+...+100squ.101)= Value of (1.2squ+2.3squ+...+100.101Sq)/(1squ.2+2squ.3+...+100squ.101)=
Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee
Solving IIT-JEE question in 30 seconds!! Solving IIT-JEE question in 30 seconds!!
Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee Q) If 1/(2×3×4)+1/(3×4×5)+1/(4×5×6) +…..+1/(100×101×102)=𝑘/101, then 34 k #jeemains #class12 #jee