Let \(a_1, a_2, \ldots \ldots, a_{21}\) be an AP such that \(\sum_{n=1}^{20} \frac{1}{a_n a_{n+1....

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Let \[{a_1},{a_2},{a_3},........\] be in an A.P. such that \[\sum\limits_{k = 1}^{12} {{a_{2k - 1}}} Let \[{a_1},{a_2},{a_3},........\] be in an A.P. such that \[\sum\limits_{k = 1}^{12} {{a_{2k - 1}}}
Let a1,a2...a21 be an AP such that Sigma (n=1 to 20) (1/(an)(an+1).If the sum of this AP is 189 Let a1,a2...a21 be an AP such that Sigma (n=1 to 20) (1/(an)(an+1).If the sum of this AP is 189
Let \[{a_n} \] be a sequence such that \[{a_0} = 0{a_1} = \frac{1}{2}\] and \[2{a_{n + 2}} = 5{a Let \[{a_n} \] be a sequence such that \[{a_0} = 0{a_1} = \frac{1}{2}\] and \[2{a_{n + 2}} = 5{a
SHOW THAT 1/(√a1 +√a2) + 1/(√a2 + √a3) +..... + 1/(√an-1 + √an) = (n-1)/(√a1 + √an) #maths #video SHOW THAT 1/(√a1 +√a2) + 1/(√a2 + √a3) +..... + 1/(√an-1 + √an) = (n-1)/(√a1 + √an) #maths #video
MATH OLYMPIAD | EVALLUATE : 1/π‘Ž_1 +1/π‘Ž_2 +1/π‘Ž_3 +…+1/π‘Ž_20 𝑖𝑓 π‘Ž_𝑛=√(1+(1+1/𝑛)^2 )+√(1+(1βˆ’1/𝑛)^2 ) MATH OLYMPIAD | EVALLUATE : 1/π‘Ž_1 +1/π‘Ž_2 +1/π‘Ž_3 +…+1/π‘Ž_20 𝑖𝑓 π‘Ž_𝑛=√(1+(1+1/𝑛)^2 )+√(1+(1βˆ’1/𝑛)^2 )
Q) Let π‘Ž_1,π‘Ž_2,π‘Ž_3…. be in an A.P. such that βˆ‘129_(π‘˜=1)^12β€Š π‘Ž_(2π‘˜βˆ’1)=βˆ’72/5 π‘Ž_1,π‘Ž_1β‰ 0 If βˆ‘129_(π‘˜=1)^ Q) Let π‘Ž_1,π‘Ž_2,π‘Ž_3…. be in an A.P. such that βˆ‘129_(π‘˜=1)^12β€Š π‘Ž_(2π‘˜βˆ’1)=βˆ’72/5 π‘Ž_1,π‘Ž_1β‰ 0 If βˆ‘129_(π‘˜=1)^
Let the sequence \( a_{1}, a_{2}, a_{3}, \ldots, a_{n}, \ldots \) form an A.P. Then, \( a_{1}^{2... Let the sequence \( a_{1}, a_{2}, a_{3}, \ldots, a_{n}, \ldots \) form an A.P. Then, \( a_{1}^{2...
a1, a2, a3...a21 be an AP such that Sigma 1/(an)(an+1) = 4/9, Sequence and Series, Maths By Ajay Sir a1, a2, a3...a21 be an AP such that Sigma 1/(an)(an+1) = 4/9, Sequence and Series, Maths By Ajay Sir